Slew Rate — the op amp speed limit
Slewing behavior of op amps is often misunderstood. It’s a meaty
topic so let’s sort it out.
The input circuitry of an op amp circuit generally has a very small
voltage between the inputs ideally zero, right? But a sudden change in the
input signal temporarily drives the feedback loop out of balance creating a
differential error voltage between the op amp inputs. This causes the output to
race off to correct the error. The larger the error, the faster it goes… that
is until the differential input voltage is large enough to drive the op amp
into slewing.
If the input step is large enough, the accelerator is jammed to
the floor. More input will not make the output move faster. Figure 1 shows why
in a simple op amp circuit. With a constant input voltage to the closed-loop
circuit there is zero voltage between the op amp inputs. The input stage is
balanced and the current IS1 splits equally between the two input transistors.
With a step function change in Vin, greater than 350mV for this circuit, all
the IS1 current is steered to one side of the input transistor pair and that
current charges (or discharges) the Miller compensation capacitor, C1. The
output slew rate (SR) is the rate at which IS1 charges
C1, equal to IS1/C1.
There are variations, of course. Op amps with slew-enhancement add circuitry to detect this
overdriven condition and enlist additional current sources to charge C1 faster
but they still have a limited slew rate. The positive and negative slew rates
may not be perfectly matched. They are close to equal in this simple circuit
but this can vary with different op amps. The voltage to slew an input stage
(350mV for this design) varies from approximately 100mV to 1V or more,
depending on the op amp.
While the output is slewing it can’t respond to incremental
changes in the input. The input stage is overdriven and the output
rate-of-change is maxed out. But once the output voltage nears its final value
the error voltage across the op amp inputs reenters the linear range. Then the
rate of change gradually reduces to make a smooth landing at the final value.
There nothing inherently wrong with slewing an op amp—no damage or
fines for speeding. But to avoid gross distortion of sine waves, the signal
frequency and/or output amplitude must be limited so that the maximum slope
does not exceed the amplifier’s slew rate. Figure 2 shows that the maximum
slope of a sine wave is proportional to VP and frequency. With 20% less than the
required slew rate, output is distorted into a nearly triangle shape.
Large-signal square waves with very fast edges tilt on the rising
and falling edges according to the slew rate of the amplifier. The final
portion of a rising or falling edge will have rounding as the amplifier reaches
its small-signal range as shown in figure 1.
In a non-inverting circuit, a minimum 350mV step is required to
make this op amp slew, regardless of gain. Figure 3 shows the slewing behavior
for a 1V input step with gains of 1, 2 and 4. The slew rate is the same for
each gain. In G=1, the output waveform transitions to small-signal behavior in
the final 350mV. In G=2 and G=4 the small-signal portion is proportionally
larger because the error signal fed back to the inverting input is attenuated
by the feedback network. If connected in a gain greater than 50, this amplifier
would be unlikely to slew because a 350mV step would overdrive the output.
Slew rate is usually specified in V/μs, perhaps because early
general purpose op amps had slew rates in the range of 1V/μs. Very high speed
amplifiers are in the 1000V/μs
range, but you would rarely see it written as 1kV/μs or 1V/ns. Likewise, a
nanopower op amp might be specified as 0.02V/μs but seldom as 20V/ms or 20mV/μs. There’s just no good
reason why for some things; it’s just the way we
do it. :-)
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courtsy: bruce , electronics lab.com
thanks : WGK